Question 252583
The original problem was:
{{{(x^2 /4) -1-2x=-1}}}
multiply everything by 4.
{{{x^2 - 4 - 8x = -4}}}
{{{x^2 - 8x = 0}}}
{{{(x)(x-8) = 0}}}
x=0 OR x = 8.