Question 252575
Which of the following quadratic equations has solutions x=6a and x=-3b?
A. x^2 - 18ab=0
B. x^2 - x(3b-6a)-18ab=0
C. x^2 - x(3b+6a) +18ab= 0
D. x^2 + x(3b-6a)- 18ab=0
E. x^2 + x(3b+6a) + 18ab=0 
---------------------
Multiply it and see.
(x-6a)*(x+3b) = x^2 + x(6a-3b) - 18ab
it's B