Question 252554
{{{x^2-3x-21 = y}}} and {{{x^2-4x-18 = y}}} , what is the product of 
{{{(x-5)(x-7)(x+2)(x+3)}}} in terms of y?

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Since {{{x^2-3x-21 = y}}} and {{{x^2-4x-18 = y}}}, then

{{{x^2-3x-21 = x^2-4x-18}}}, since both equal {{{y}}}

simplifying:

{{{-3x-21=-4x-18}}}

{{{x=3}}}

So therefore

{{{y =x^2-3x-21 = 3^2-3(3)-21=9-9-21=-21}}}

{{{(x-5)(x-7)(x+2)(x+3)=(3-5)(3-7)(3+2)(3+3)=(-2)(-4)(5)(6)=240}}}

So you're asking how to write 240 in terms of -21?

One way would be {{{240=(-21)(-240/21) = (-21)(80/7)}}}

Somehow I think you're wanting something else, but I 
don't know what else.  Did you mistype something?

Edwin</pre>