<PRE><B>Question 252492</B>
The second cyclist travels @ 10mph and starts 3 hourss after the first cyclist who is traveling @ 6mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist srtarted biking?
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2nd Cyclist DATA:
rate = 10 mph ; time = x-3 hrs ; distance = rt = 10(x-3) miles
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1st Cyclist DATA:
rate = 6 mph ; time = x hrs ; distance = rt = 6x miles
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Equation:
distance = distance
10x-30 = 6x
4x = 30
x = 7.5 hrs (1st cyclist time)
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x-3 = 4.5 hrs (2nd cyclist time)
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Cheers,
Stan H.</PRE>