Question 250855
The original problem was:
{{{a(t) = 48/3t+4}}}
We can rewrite this as
{{{ Y = 16/t + 4}}}
To find an inverse, first switch the t and y.
{{{t = 16/Y + 4}}}
Now, solve for the new Y.
{{{Yt = 16 + 4Y}}}
{{{Yt - 4Y = 16}}}
{{{ Y^(-1) = 16/(t-4)}}}