Question 252484
It may help to turn all exponents into positives, like this:
{{{(3*P^3*Y^5/x^2)^(-2)}}}*{{{(3/(x*y))^2}}}
Next, notice the first parenthesis still has a big negative exponents on the outside. We will flip that fraction and call the exponent regular 2, like this:

{{{(X^2 / (3*p^3*Y^5))^2}}} * {{{(3/(x*y))^2}}}

Now we can apply the powers using the power rule - when you raise a power to a power, you multiply the exponents.

{{{X^4 / (3^2*p^6*Y^10))}}} * {{{3^2/(x^2*y^2)}}}
It might be hard to see here, but the 3^2 drop out as do an X^2 piece. THis leaves us with
{{{ X^2 / (P^6*Y^12)}}}