Question 251074
Multiply.
{{{(x^2)*(x^2+6x+9)/(x^2-9)*(16x^3)}}}
I assumed a minus sign between X^2 and 9 and then multiplication sign separating denominator fractions.
first, factor everything.
numerator is
x^2(x+3)(x+3).
denominator is
(x+3)(x-3)(16x^3).
together, we get
{{{x^2(x+3)(x+3)}}} / {{{(x+3)(x-3)(16x^3)}}}
Now, we cancel: x=3 from top and bottom. X^2 from top and bottom. We get
{{{(x+3)}}} / {{{(x-3)(16x)}}}

-----
Divide.
{{{(3y+12)÷(9y+36)}}}/{{{(8y^3)(16y^3)}}}
First step multiply by reciprocal:
{{{(3y+12)*(8y^3)(16y^3)/(9y+36)}}} 
Second step is to factor.
numerator becomes: {{{3(y+4)*8y^3*16y^3}}}
denominator becomes: {{{9(y+4)}}}
together we get:{{{3(y+4)*8y^3*16y^3}}} / {{{9(y+4)}}}
canceling the y+4 and the 3 with the 9, we get:
128y^6 / 3
-------
Perform the indicated operation. When no operation is indicated, simplify the rational expression completely.
(i) (10m^4)×/(9a^2) (3a^2b) -> I am not clear as to the x/ next to each other.

(ii) (3x^2-5x)/(18x-30)
step 1 - factor: x(3x-5) / 6(3x-5)
step 2 - reduce: x/6.