Question 252407
Write an equation in slope-intercept form of line that passes thru -5,7
And is perpendicular to the graph of y = {{{-3/8}}}x - 1{{{1/4}}}
:
Find the slope of the perpendicular line (m2):
m1 * m2 = -1
:
{{{-3/8}}} * m2 = -1
m2 = -1 * {{{-8/3}}}
m2 = {{{8/3}}}
:
use the point/intercept formula: y - y1 = m(x - x1)
where
m = {{{8/3}}}
x1 = -5
y1 = 7
:
y - 7 = {{{8/3}}}(x - (-5))
y - 7 = {{{8/3}}}(x + 5)
y - 7 = {{{8/3}}}x + ({{{8/3}}}*5)
y - 7 = {{{8/3}}}x + {{{40/3}}}
y  = {{{8/3}}}x + {{{40/3}}} + 7
y  = {{{8/3}}}x + {{{40/3}}} + {{{21/3}}}
y  = {{{8/3}}}x + {{{61/3}}}
which is
y = 2{{{2/3}}}x + 20{{{1/3}}}