Question 31864
You have two points: (2,350) and (5,530)
You need an equation of the form y=mx+b
m=(530-350)/(5-2)
m=180/3
m=60
Using x=2, y=350, and m=(60) we solve for "b", as follows:
350=(60)(2)+b
b=230
Therefore the equation is y=(60)x+230
Finding the value of the clock after 10 years,
let x=10 to get y=60(10)+230
y=600+230
y=$830