Question 252391
y= -3x^2-6x-5
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Use whatever x values you wish and calculate the y values.
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x intercepts (when y=0) 
-3x^2-6x-5=0
There are none. There are no real zeros. Quadratic formula.
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y intercepts (when x=0)
y=-5
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vertex at x:
-b/2a
x= -(-6)/2(-3)
=6/-6=-1
at y=-3+6-5=-2
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{{{graph(500,500,-10,10,-10,10,-3x^2-6x-5)}}}
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Ed