Question 252314
This requires a few equations. First Let N = nickel, D = dime, and Q = quarter. From the first sentence, we get
{{{5N + 10D + 25Q = 375}}}
This equation is the "value" equation. Notice also I don't use decimal points. Easier to get rid of them I think. Next,
{{{D + 3 = Q}}} "Three more quarters than dimes".
{{{2Q = N }}} "Twice as many nickels as quarters}}}
Put all of this together using only Q, we get
5(2Q) + 10(Q-3) + 25Q = 375
Solving for Q, you get Q = 9.
Find the others, N = 18 and D = 6. So we have 18 nickels, 6 dimes, and 9 quarters.