Question 252195
The quadratic formula is

{{{-b +-sqrt(b^2-4*a*c))}}}/{{{(2*a)}}}

Looking at your equation of {{{p^2+2p-5 = 0}}}

we can see that a = 1, b = 2 and c= -5. Don't forget the signs.

PLug these into the quadratic and you get

-2 +- sqrt(4 - 4*1*-5) / 2(1)

(-2 +- sqrt(24))/2

(-2 +- 2sqrt(6)) / 2

-1 +- sqrt(6)