Question 31788
Equation of the line perpendicular to 3x-4y=9 is 4x+3y=k
Since it passes through the point (-3,4), it must satisfy the equation.
4x+3y=k
=> 4(-3)+3(4)=k
=> -12+12=k
=>k=0
The required equation is 4x+3y=0
When translated to slope-intercept form,
3y=-4x
=> y = (-4/3)x