Question 252093
The hypotenuse of a right triangle is 2cm longer than one leg and 4cm longer then the other. 
a.draw and label a diagram
Let one leg be x-2.
hypotenuse = x
Other leg = x-4
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b.let x represent the length of the hypotenuse. Use the pythagreon thereom to write an equation to solve for x.
Equation:
x^2 = (x-2)^2 + (x-4)^2
x^2 = x^2-4x+4 + x^2-8x+16
x^2 = 2x^2 - 12x + 20
x^2-12x+20 = 0
(x-10)(x-2) = 0
x = 2 or x = 10
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Only solution is x=10 because all sides must be positive.
hypotenuse = 10
leg = 10-2 = 8
leg = 10-4 = 6
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Cheers,
Stan H. 
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