Question 252074
two airplanes start out 10,000 miles apart.
 one plane heads east and the other heads west traveling at a rate 100 mph faster than the other plane. after how many hours will they pass each other?
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There are multiple solutions to this problem
Let s = speed of the slower plane
then
(s+100) = speed of the faster speed
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Both planes travel the same length of time (t)
:
Write a distance equation Dist = speed * time:
:
Slow plane dist = fast plane dist = 10,000 miles
ts + t(s+100) = 10000
ts + ts + 100t = 10000
2ts + 100t = 10000
t(2s + 100) = 10000
t = {{{10000/(2s+100)}}} = {{{10000/(2(s+50))}}} = {{{5000/(s+50)}}}
:
 t = {{{5000/(s+50)}}}
:
Enter the speed (s) of the slower plane to get the time (t)
For example
s = 200 mph; t = 20 hrs
s = 1200 mph; t = 4 hrs