Question 246756
Let n and n+1 be two consecutive integers. Now {{{SQRT(n+n+1)}}} = 11 gives us {{{SQRT(2n+1)}}} = 11. To get rid of the square root, you square both sides to get 2n+1 = 121. Solving for n, we get n = 60. So our two consecutive integers are 60 and 61.