Question 251998
equations are:


2x - 2y = 4
3y - x = 1


presumably you want to solve them simultaneously.


use the second equation to solve for y in terms of x and then use that value to substitute in the first equation to solve for x.


second equation is:


3y - x = 1


add x to both sides and subtract 1 from both sides to get:


3y - 1 = x


take the value of x in terms of y and substitute in the first equation.


first equation is:


2x - 2y = 4


substitute 3y-1 for x to get:


2*(3y-1) - 2y = 4


simplify by performing indicated operatioons to get:


6y - 2 - 2y = 4


combine like terms to get:


4y - 2 = 4


add 2 to both sides of equation to get:


4y = 6


divide both sides of equation by 4 to get:


y = (6/4)


substitute for y in the second equation and solve for x.


second equation is:


3y - x = 1


replace y with (6/4) to get:


3*(6/4) - x = 1


simplify by performing indicated operations to get:


(18/4) - x = 1


add x to both sides of this equation and subtract 1 from both sides of this equation to get


(18/4) - 1 = x


simplify to get:


x = (14/4)


you have:


x = (14/4)
y = (6/4)


substitute in both equations to confirm these values will solve both equations (both equations will be true)


your equations are:


2x - 2y = 4
3y - x = 1


these equations becomes:


2*(14/4) - 2*(6/4) = 4
3*(6/4) - (14/4) = 1


simplifying, these equations become:


28/4 - 12/4 = 4
18/4 - 14/4 = 1


simplifying further, these equations become:


16/4 = 4
4/4 = 1


both these equations are true, so the values for x and y are good.


x = (14/4)
y = (6/4)


these answers are the same as:


x = 3.5
y = 1.5