Question 251986
Answer: Let the two consecutive positive integers be n and n+1
Then, (n+n+1)(n+1-n)+8 = n^2 +(n+1)^2
         2n+1+8        = n^2 + n^2 + 2n+1
              8        = 2n^2
              4        = n^2
              2        = n
So the required numbers are 2,3