Question 31775
Hello!
Your work has a slight mistake.

You have expression {{{x^3-26x^2+48x}}}

Taking x as common factor:

{{{x*(x^2-26x+48)}}}

Now you can factorise the quadratic equation inside using its roots. The roots of this equation are 24 and 2:

*[invoke solve_quadratic_equation 1, -26, 48]

Therefore,
{{{x^2-26x+48 = (x-24)(x-2)}}}

So the whole expression becomes:

{{{x(x-24)(x-2)}}}


I hope this helps!
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