Question 31749
(W+2X)^8
AS PER BINOMIAL THEOREM IN EXPANSION OF (X+A)^N..THE GENERAL TERM IS GIVEN BY
T(R+1)=NCR*(X^(N-R))*(A^R)
HERE WE HAVE W AS X AND 2X AS A AND N=8....SO...
T(R+1)=NCR*W^(N-R)*(2X)^R.....WE WANT T3....R+1=3......R=2......
T3=8C2*W^(8-2)*(2X)^2=(8*7/2)*W^6*4X^2=112W^6*X^2
B IS THE ANSWER