Question 251809
what is 2x to the 4th y to the -4 z to the -3 over 3x to the 2nd y to the -3 z to the 4th ?

(2x^4*y^(-4)*z^(-3))/(3x^2*y^(-3)*z^4) = 
(2/3)[((x^4)*(x^(-2))*((y^(-4))*(y^(+3))*((z^(-3)*z^(-4))] =
(2/3)[(x^2)*(y^(-1))*(z^(-7))]