Question 251793
First, get your equation into slope-intercept form:  y = mx + b.
.
{{{y - 5x = 6}}}
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Add 5x to both sides.
{{{y = 5x + 6}}}
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So we immediately recognize several things.
a. It is a linear equation (i.e., no exponents).
b. Since it a linear equation, its graph will be straight line.
c. The slope, m, is 5.  That means for every 1-unit change in x, there is a 5-unit change in y.
d. The line will intercept the y-axis where x=0.  By inspection we can see that is 6, so the point is (0,6).
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Your question is the x-intercept, which is where the line crosses the x-axis.  That means y = 0.
So we solve the equation:
{{{0 = 5x + 6}}} 
or
{{{5x + 6 = 0}}}
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Subtract 6 from both sides.
{{{5x = -6}}}
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Divide both sides by 5.
{{{x = -(6/5) = -1.2}}}
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So the point will be (-1.2,0).
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We also can graph the equation.
{{{
graph(500,500,-10,10,-10,10,5*x+6)
}}}