<PRE><B>Question 251783</B>
 Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of each jet?
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closing speed for the two jets is x + x+100 = 2x+100 km/h
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Equation:
time = distance/rate = 4000/(2x+100) hrs = 2.5 hrs
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2000/(x+50) = 2.5
2.5x + 125 = 2000
2.5x = 1875
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x = 750 km/h (speed of the slower jet)
x+100 = 850 km/h (speed of the faster jet)
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Cheers,
Stan H. 
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