Question 31732
Hello!
What you should do here is is take {{{1/(5a-10)}}} as common factor. Notice that {{{10a-20}}} is simply {{{2(5a-10)}}}. Therefore, you would get the expression:

{{{(1/(5a-10))(4a - (3a)/2)}}}

Doing the subtraction in the second term, we get:

{{{(1/(5a-10))((5/2)a)}}}

So the final answer would be:

{{{ (5a)/(10a-20)}}}


I hope this helps!
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