Question 251746
2) Given that log 2 ≈ 0.301 and log 3 ≈ 0.477, find the following. log6 27
.477 * 3 = 1.431 (log[10](27))
.301 + .477 = .778 (log[10](6))
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Change of base formula: 1.431/.778=1.839 (log[6](27))
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Ed