Question 251660
(10a+b)*(10c+d)=1484
b*d=24
a*c=10
There is not enough info to form 4 equations
but we know that b*d=24 
there are only two possible single digit factors

6*4=24
8*3=24


a=2 or a=5
c=2 or c=5
b=6 or b=4
d=6 or d=4
b=8 or b=3
d=8 or d=3
from our equations we know
b = 4 a   so must be 8 and a must be 2
8=4*2 
a=2 c=5
if a=2 then c must be 5
if b is 4 then d must be 6

a*c=10
b=8 d=3
b*d=24
(10a+b)*(10c+d)=1484
28*53=1484

so the two numbers are 28 and 53
2*5=10
8*3=24