Question 251605
i need to solve this problem with a system of three equations for age: 
The sum of the ages of three brothers, Andre, Brad, and Carlos is 48.
a + b + c = 48
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In ten years, twice Brad's age will be 3 years less than the sum of his brothers ages. six years ago,
2(b+10) = (a-6) + (c-6)-3
2b+20 = a+c-15
a - 2b +c = 35
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Carlos's age was four years younger than the sum of his brothers ages. 
c = a + b - 4
a + b - c = 4
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how old are the brothers now?
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Gather the equations:
a  +   b   +  c =  48
a  -  2b   +  c =  35
a  +   b   -  c =  4
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I used a matrix method and got:
a = 21 2/3
b = 4 1/3
c = 22
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Cheers,
Stan H.