<PRE><B>Question 251522</B>
Height of a ball. If a ball is thrown straight upward at
40 feet per second from a rooftop 24 feet above the
ground, then its height in feet above the ground t seconds
after it is thrown is given by
h(t)= 16t^2 + 40t + 24.
a) Find 
 h(0) = 24
 h(1) = -16 + 40 + 24 = 48
 h(2) = -64 + 80 + 24 = 60
 h(3) = -144 + 120 + 24 = 0
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b) Rewrite the formula with the polynomial factored
completely.
h(t) = (-8)(2t^2 - 5t -3)
h(t) = -8[2t^2 -6t + t - 3]
h(t) = -8[2t(t-3)+(t-3)]
h(t) = -8(t-3)(2t+1)
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c) Find h(3) using the result of part (b).
h(3) = -8(0)(7) = 0
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If you can, please show the detailed work, thank you
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Cheers,
Stan H.</PRE>