Question 251484
Since its a similar triangle;
so, let A1 = the area of the larger triangle
        A2 = the area of the smaller triangle
        P1 = the perimeter of the larger triangle
        P2 = the perimeter of the smaller triangle

by ratio & proportion:
    A1 = 16*A2 ----(1)
   (A1/A2) = (P1/P2)^2 ----(2)
   substitute (1) into (2)
   [(16*A2)/A2] = (P1/P2)^2
taking the sqrt. on both sides;
   4P2 = P1
thus, the ratio is:
   4:1 --- answer