Question 251278
Hello, 
Since we are dealing with a right triangle we can use the following formula:
a^2 + b^2 = c^2  Let "a" be the height of the wall where the latter is touching.
We can represent the length of the latter as b+3, therefore we can plug these into the formula:
9^2 + b^2 = (b+3)^2 rewritten as:
81 + b^2 = b^2 +6b + 9 Subtract b^2 from both sides and subtract 9 from both sides will give us:
72 = 6b Divide 6 into both sides will be:
12=b Now we know the latter is 15 feet long and the base is 12 feet. 
RJ 
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