Question 251182
(a+7)/ 3a^2+14a-49 over a^2+8a+7 
Divide and, if possible, simplify.
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(a+7)/[(3a-7)(a+7)] over [(a+7)(a+1)]
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Cancel(a+7) to get:
1/[(3a-7)] over [(a+7)(a+1)]
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Rewrite:
[1/(3a-7)]/[(a+7)(a+1)]/1
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Invert the denominator and multiply:
= 1/[(3a-7)(a+7)(a+1)]
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Cheers,
Stan H.