<PRE><B>Question 4136</B>
 Let the deceleration be a m/h^2.
 Use solve v^2 = 2a S , 50^2 = 2a * 15 to find 
 a = 250/3 m/ h^2.
 
 When v = 150, S = v^2/ 2a = 150^2 / (500/3) = (9 * 2500)* (3/500)
                 = 27* 5 = 135 meters.

 Or use V1^2/S1 = V2^2/S2 and solve
   50^2/15 = 150^2/S2 
 or 1/15 = 9/S2
 to get S2 = 135 m.

 Kenny</PRE>