Question 251086
{{{R = 2GM/c^2}}}
Inserting the values for the sun into this equation we get:
{{{R = (2(6.7*10^(-11))(2*10^30))/(3*10^8)^2}}}
Now we simplify. In the numerator I am going to use the Commutative and Associative Properties for Multiplication to rearrange the factors to gather the powers of 10 together and the other numbers together. This will make the simplification easier:
{{{R = ((2*6.7*2)*(10^(-11)*10^30))/(3*10^8)^2}}}
{{{R = (26.8*10^19)/(9*10^16)}}}
{{{R = (26.8/9)*10^3}}} which is approximately 3000.<br>
I did some investigating and 700,000 is the actual radius of the sun. The answer we have of 3000 tells us that if the sun had the same mass but was only 3000 km is radius it would be a black hole.