Question 31645
(3x^0)(-2x)^4/(24x^5)
= [(3*1){(-2x)^4}]/(24x^5)
= (3){(-2)^4)}(x^4)/(24x^5)
= 3*16*x^4/(24x^5)
= (48/24)[x^(4-5)]
= 2x^-1
= 2/x

Answer: 2/x