Question 251039
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Let *[tex \Large w] represent the width.  Then *[tex \Large 1.6w] is the length (if you are using 1.6 as an approximation of the golden ratio).  The area is the length times the width, so the area as a function of the width is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A(w)\ =\ 1.6w^2]


Substitute the given value for the area:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 1.6w^2\ =\ 9000]


And solve for *[tex \Large w] to get the width in meters.  Multiply your result for the width times 1.6 to get the length.  



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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