Question 250860
Let x = integer
Let x+2 = consecutrive odd integer
Let x+4 = the next odd consecutive integer
If their sum is 10 less than 4 times the least integer, 
the equation becomes: {{{x+(x+2)+(x+4)=4x-10}}}


Now solve for x to find the least integer.
{{{x+(x+2)+(x+4)=4x-10}}}
{{{3x+6=4x-10}}}
{{{3x-4x=-10-6}}}
{{{-x=-16}}}
{{{x=16}}}  <--- this is the least integer