<PRE><B>Question 250765</B>
FIND THREE CONSECUTIVE POSITIVE EVEN WHOLE NUMBERS SUCH THAT THE SUM OF THE SQUARE OF THE TWO SMALLER NUMBERS IS 20 MORE THAN THE SQUARE OF THE LARGEST NUMBER.
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1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:

(2x-2)^2 + (2x)^2 = (2x+2)^2 + 20
4x^2 - 8x + 4 + 4x^2 = 4x^2 + 8x + 4 + 20
4x^2 - 16x -20 = 0
x^2 - 4x - 5 = 0
(x-5)(x+1) = 0
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Positive solution:
x = 5
1st: 2x-2 = 8
2nd: 10
3rd: 12
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Cheers,
Stan H.</PRE>