Question 250765
FIND THREE CONSECUTIVE POSITIVE EVEN WHOLE NUMBERS SUCH THAT THE SUM OF THE SQUARE OF THE TWO SMALLER NUMBERS IS 20 MORE THAN THE SQUARE OF THE LARGEST NUMBER.

Let x be the smallest of the three consecutive postive even integers.
Then the other two integers are x+2 and x+4.

We have then:

x^2 + (x+2)^2 = (x+4)^2 + 20

Solve for x and then calculate x+2 and x+4.