Question 250632
{{{4x-3y=6}}}
{{{-3y=-4x+6}}}
{{{y=(4/3)x-2}}}
Perpendicular lines’ slopes have the following relationship:
{{{m1*m2=-1}}}
{{{(4/3)*m2=-1}}}
{{{m2=-(3/4)}}}
Use the point-slope form of a line with point (xp, yp) and slope m:
{{{y-yp=m(x-xp)}}}
{{{y-0=-(3/4)(x-(-3))}}}
{{{y=-(3/4)x-(9/4)}}}
{{{ graph( 300, 300, -5, 5, -5, 5, -(3/4)x-(9/4), 
(4/3)x-2) }}}