Question 250622
{{{(4x + 3)^2 = 5}}}
{{{16x^2+24x+9 = 5}}}
{{{16x^2+24x+4 = 0}}}
{{{4x^2+6x+1 = 0}}}
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-6 +- sqrt( 6^2-4*4*1 ))/(2*4) }}} 
{{{x = (-6 +- sqrt( 36-16 ))/(8) }}} 
{{{x = (-6 +- sqrt( 20 ))/(8) }}}
{{{x = (-6 +- 2*sqrt( 5 ))/(8) }}}
{{{x = (-3 +- sqrt( 5 ))/(4) }}}
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or more directly,
{{{(4x + 3)^2 = 5}}}
{{{4x + 3 = 0 +- sqrt(5)}}}
{{{4x = -3 +- sqrt(5)}}}
{{{x = (-3 +- sqrt(5))/4}}}