Question 250625
{{{2L+2W=34}}}
1.{{{L+W=17}}}
2.{{{L^2+W^2=13^2}}}
From 1,
{{{L=17-W}}}
{{{L^2=289-34W+W^2}}}
Subsitute into 2,
{{{L^2+W^2=13^2}}}
{{{289-34W+W^2+W^2=13^2}}}
{{{2W^2-34W+289=169}}}
{{{2W^2-34W+120=0}}}
{{{(2W-10)(W-12)=0}}}
Two solutions:
{{{2W-10=0}}}
{{{2W=10}}}
{{{W=5}}}
Then 
{{{L+W=17}}}
{{{L=12}}}
.
.
.
The second solution is 
{{{W-12=0}}}
{{{W=12}}} 
{{{L=5}}}
.
.
.
The area of the rectangle is
{{{A=LW=(5)(12)=60 m^2}}}