Question 250341
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The secant is the reciprocal of the cosine, so if *[tex \LARGE \sec(\Theta)\ =\ \frac{10}{6}] then *[tex \LARGE \cos(\Theta)\ =\ \frac{3}{5}].


Since *[tex \LARGE \cos^2(\Theta)\ +\ \sin^2(\Theta)\ = 1], if *[tex \LARGE \cos(\Theta)\ =\ \frac{3}{5}], then *[tex \LARGE \sin(\Theta)\ =\ \frac{4}{5}]


Verification of the last calculation is left as an exercise for the student.


The cosecant is the reciprocal of the sine, so if *[tex \LARGE \sin(\Theta)\ =\ \frac{4}{5}] then *[tex \LARGE \csc(\Theta)\ =\ \frac{5}{4}]


Tangent is the sine over the cosine, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan(\Theta)\ =\ \frac{\sin(\Theta)}{\cos(\Theta)}\ =\ \frac{\frac{4}{5}}{\frac{3}{5}}\ =\ \frac{4}{3}]


Cotangent is the reciprocal of the tangent so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cot(\Theta)\ =\ \frac{3}{4}]


There is no way determine the area of the triangle for certain.  Knowing that the secant is 10 over 6 only guarantees that the RATIO of the lengths of the sides is 10 to 6.  A right triangle with legs of 10,000 miles and 6,000 miles has an angle whose secant is 10 over 6, but so does one that has legs of 40 angstroms and 24 angstroms.  The only thing that you can say for certain is that for some real number *[tex \Large k], the area is *[tex \Large 5k\,\cdot\,3k\ =\ 15k^2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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