Question 250336
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I can't do this one for you because you only provided the equation.


However, here's how you do it:


Note that your given equation is already in slope-intercept form, *[tex \LARGE y\ =\ mx\ +\ b].  That means that you can determine the slope of your given line by inspection of the coefficient on *[tex \LARGE x].


Next remember that the slopes of parallel lines are equal, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


Now use the point-slope form of the equation of a line to derive an equation for the desired line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the slope you determined in the first step.


Finally, depending on the instructions given with your assignment, or perhaps on the use you intend to put the equation that you have just derived, you may want to put the equation into a different form such as slope-intercept (as described above) or standard form: *[tex \LARGE Ax\ +\ By\ =\ C].  Note that some texts require that A, B, and C be integers for proper standard form.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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