Question 250274
Let x = number
Let (1/3)x = the other number
Since their sum is 92, the equation becomes:


{{{x+(1/3)x=92}}}


The above expression is the same as {{{1x+(1/3)x=92}}} right?
So, in order to add the coefficients, we can also say:


{{{(3/3)x+(1/3)x=92}}}


{{{(4/3)x=92}}}


{{{x=92(3/4)}}}


{{{x=69}}} ...then... {{{(1/3)x=(1/3)69=69/3=23}}}


{{{69+23=92}}}  <--- answers check!