Question 250139
I need to graph this inequality on a plane
2x+3y<6
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1st: graph the boundary line which is the EQUALITY 2x+3y=6
3y=-2x+6
y = (-2/3)x + 2
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Graph this as a dashed line because it is not part of the solution.
{{{graph(400,300,-10,10,-10,10,(-2/3)x+2)}}}
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2nd: shade the half-plane BELOW the boundary because you want
y to be LESS THAN (-2/3)x+2
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{{{graph(400,300,-10,10,-10,10,y<(-2/3)x+2)}}}
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Cheers,
Stan H.
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