Question 250053
1.{{{3x-2y-z=1}}}
2.{{{2x-2y  =4}}}
3.{{{2x   -2z=-12}}}
From 2,
{{{2y=2x-4}}}
From 3,
{{{2z=2x+12}}}
{{{z=x+6}}}
Substitute into 1 and solve for x.
1.{{{3x-2y-z=1}}}
{{{3x-(2x-4)-(x+6)=1}}}
{{{3x-2x-x+4-6=1}}}
{{{-2=1}}}
Since this leads to an inconsistency, there is no solution.