Question 250018
{{{log base x[log base 2(log base 3 of 9)]=2}}}
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log3(9) = 2 so your problem becomes:
{{{log base x[log base 2(2)]=2}}}
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log2(2) = 1 so your problem becomes:
logx(1) = 2
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x^2 = 1
x^2-1 = 0
(x-1)(x+1) = 0
x = 1 or x=-1
But -1 cannot be the base of a log.
So x = 1 is the only solution.
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Cheers,
Stan H.