<PRE><B>Question 249888</B>
A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took 3 hours less time. Find the speed going
:
Let s = original speed
then
2s = return speed
:
Write time equation Time = dist/speed
:
original time - return time = 3 hrs
{{{120/s}}} - {{{120/(2s)}}} = 3
reduce fraction
{{{120/s}}} - {{{60/s}}} = 3
multiply by s
120 - 60 = 3s
:
60 = 3s
s = {{{60/3}}}
s = 20 mph hr is going speed
:
:\
Check the times
120/20 = 6 hr
120/40 = 3 hr
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differ = 3 hrs</PRE>