Question 249876
<font face="Garamond" size="+2">


*[tex \LARGE x\ =\ -2] means exactly what it says.  The *[tex \LARGE x] in that statement is the exact same *[tex \LARGE x] in the given polynomial, so perform the substitution and do the arithmetic:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -4x^3\ +\ 2x^2\ +\ 5x\ -\ 7]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -4(-2)^3\ +\ 2(-2)^2\ +\ 5(-2)\ -\ 7]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>