Question 249858
Let the width be x
So length = x + 2
Thus area = x*(x+2)

Given Area = 63
=> x(x+2) = 63
=> x^2 + 2x - 63 = 0
=> x^2 + 9x - 7x -63 = 0
=> x(x+9) -7(x + 9) = 0
=>(x-7)(x+9) = 0
=> x = 7 or x = 9

Thus the width of the walkway is 7 and the length is 9. So the perimeter is 
2*(7 + 9)
=2*16
=32